Question

gkghj

Answer 1

do you know how to start this ??

Answer 2

what grade is this?

Answer 3

do you want help or not?

Answer 4

She does not want you to help she only wants the answer. I tried helping her but she closed the question and opened a new one with the same question

Answer 5

wow people need to pay attention and stop begging others for the answer . she wont graduate by asking others the answers for her work

Answer 6

I know. I hate these kind of people in openstudy. They only want for answers not to learn.

Answer 7

But i'll let this slide one time.

Answer 8

x+4y+z=-10_3x-3y+6z=-21_x+2y+2z=-10

Move all terms not containing x to the right-hand side of the equation.
x=-4y-z-10_3x-3y+6z=-21_x+2y+2z=-10

Replace all occurrences of x with the solution found by solving the last equation for x. In this case, the value substituted is -4y-z-10.
x=-4y-z-10_3(-4y-z-10)-3y+6z=-21_x+2y+...

Replace all occurrences of x with the solution found by solving the last equation for x. In this case, the value substituted is -4y-z-10.
x=-4y-z-10_3(-4y-z-10)-3y+6z=-21_(-4y-...

Multiply 3 by each term inside the parentheses.
x=-4y-z-10_-12y-3z-30-3y+6z=-21_(-4y-z...

Since -12y and -3y are like terms, subtract 3y from -12y to get -15y.
x=-4y-z-10_-15y-3z-30+6z=-21_(-4y-z-10...

Since -3z and 6z are like terms, subtract 6z from -3z to get 3z.
x=-4y-z-10_-15y+3z-30=-21_(-4y-z-10)+2...

Remove the parentheses around the expression -4y-z-10.
x=-4y-z-10_-15y+3z-30=-21_-4y-z-10+2y+...

Since -4y and 2y are like terms, subtract 2y from -4y to get -2y.
x=-4y-z-10_-15y+3z-30=-21_-2y-z-10+2z=...

Since -z and 2z are like terms, subtract 2z from -z to get z.
x=-4y-z-10_-15y+3z-30=-21_-2y+z-10=-10

Move all terms not containing z to the right-hand side of the equation.
x=-4y-z-10_-15y+3z-30=-21_z=2y+10-10

Subtract 10 from 10 to get 0.
x=-4y-z-10_-15y+3z-30=-21_z=2y

Replace all occurrences of z with the solution found by solving the last equation for z. In this case, the value substituted is 2y.
x=-4y-z-10_-15y+3(2y)-30=-21_z=2y

Multiply 3 by each term inside the parentheses.
x=-4y-z-10_-15y+6y-30=-21_z=2y

Since -15y and 6y are like terms, subtract 6y from -15y to get -9y.
x=-4y-z-10_-9y-30=-21_z=2y

Since -30 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 30 to both sides.
x=-4y-z-10_-9y=30-21_z=2y

Subtract 21 from 30 to get 9.
x=-4y-z-10_-9y=9_z=2y

Divide each term in the equation by -9.
x=-4y-z-10_-(9y)/(-9)=(9)/(-9)_z=2y

Simplify the left-hand side of the equation by canceling the common factors.
x=-4y-z-10_y=(9)/(-9)_z=2y

Simplify the right-hand side of the equation by simplifying each term.
x=-4y-z-10_y=-1_z=2y

Replace all occurrences of y with the solution found by solving the last equation for y. In this case, the value substituted is -1.
x=-4(-1)-z-10_y=-1_z=2y

Replace all occurrences of y with the solution found by solving the last equation for y. In this case, the value substituted is -1.
x=-4(-1)-z-10_y=-1_z=2(-1)

Multiply -4 by each term inside the parentheses.
x=4-z-10_y=-1_z=2(-1)

Subtract 10 from 4 to get -6.
x=-6-z_y=-1_z=2(-1)

Multiply 2 by each term inside the parentheses.
x=-z-6_y=-1_z=-2

Replace all occurrences of z with the solution found by solving the last equation for z. In this case, the value substituted is -2.
x=-(-2)-6_y=-1_z=-2

Multiply -1 by each term inside the parentheses.
x=2-6_y=-1_z=-2

Subtract 6 from 2 to get -4.
x=-4_y=-1_z=-2

This is the solution to the system of equations.
x=-4_y=-1_z=-2

Answer 9

wooo what is that lol

Answer 10

The answer ;)

Answer 11

theres your answer @Mercedes00312

Answer 12

and the solution lol. since she did not want step-by-step I could just give her all of the solution

Answer 13

haha thats funny lol . she needs it thoo

Answer 14

can you stop