Question

Factor the algebraic expression below in terms of a single trigonometric function. csc2x+1

Answer 1

You mean csc^2(x) + 1

Answer 2

Pythagorean Identity:

1 + csc^2(x) = cot^2(x)

Answer 3

no it is csc 2x - 1

Answer 4

Look at what you initially typed.

Answer 5

I see that was completely wrong.

Answer 6

I believe you meant csc^2x, not csc 2x...check.

Answer 7

So retype your question carefully.

Answer 8

the equation says
Factor the algebraic expression below in terms of a single trigonometric function. csc 2x - 1.

Answer 9

Honestly, I cannot see how that is factorable.

Answer 10

Assuming that it is csc (2x). The csc of twice x.

Answer 11

Yes, I assume that is what they are stating.

Answer 12

Then, , sorry, I cannot factor it.

Answer 13

Perhaps someone else can help.

Answer 14

Would you be able to factor it if the equation was csc^2x-1?

Answer 15

If it was csc^2x, then it is factorable into:

(csc x + 1)(csc x - 1)


Becuase csc^2x is a perfect square; and 1 is a perfect square.

Answer 16

Did you want to factor it?

Answer 17

Yes.

Answer 18

Well, I factored it if it is csc^2 (x).

If it is csc(2x), then I cannot factor it.