Question

Gas law:

Answer 1

A mixture of 1.30 g sample of KClO3 and 1.10 g of MnO2 is decomposed by heat. 420 mL of O2 is collected. The resulting test tube and contents lost 0.50 g of mass during the RXN. The gas was collected over water Barometric pressure was 750mm, and the temp was 27C. Vapor pressure of H2) at 27 degrees C is 27mm.

Answer 2

I know v=NRT/P

Answer 3

@abb0t @chmvijay @aaronq

Answer 4

Any idea?

Answer 5

Help

Answer 6

what are you trying to find?

Answer 7

V on V=NRT/P

Answer 8

why is \(P_{H_2}\) important?

Answer 9

I have absolutely no idea. This is a lab question for this week. Sorry.

Answer 10

so were assuming that the 0.50 g lost is equivalent to the amount of \(O_2\) evolved?

Answer 11

Correct.

Answer 12

okay, so \(V=\dfrac{\dfrac{0.50g}{18g/mol}*R*(27+273.15)K}{750\;mm\;Hg}\)

Answer 13

just use the right R

Answer 14

Thanks so much. Can you help me with R?

Answer 15

no problem. http://en.wikipedia.org/wiki/Gas_constant

Answer 16

Your awesome.

Answer 17

Thanks!

Answer 18

Then it asks to find percent error if the theoretical molar volume is 22.41. I got 0.09242 for above. *eek*

Answer 19

@Hailey553

Answer 20

damn, i noticed i told you to divide by 18 g/mol, it should've been 32 g/mol, i was thinking of water. you should fix that