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Can someone check my work please? What mass, in grams, of fluorine gas (F2) is contained in a 10.3 liter tank at 29.8 degrees Celsius and 1.23 atmospheres? Show all of the work used to solve this problem.
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273.15 + 29.8 = 302.95K PV = nRT 1.23(10.3) = n(0.0821)(302.95) 12.669 = 24.87n n = 0.51 mol 0.51 mol F2 x [38g F2]/[1 mol F2] = 19.38g F2
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