Question

product of the real roots of the equation t^2x^2+IXI+9=0 (tis not equal to 0) does not exist
pls...explain how

Answer 1

@Mashy pls...hlp

Answer 2

\(t^{2}x^{2} + |x| + 9 = 0\)

\(|x| = - 9 - t^{2}x^{2}\)

The absolute value of what produces a negative number?

Answer 3

there is no such value which produces negative result of a number in modulus value

Answer 4

exactly :D

Answer 5

then what's the gud thing behind it...iknow dat bt how to solve it next

Answer 6

there is no solution!

Answer 7

There is no REAL solution.

Answer 8

bt why....

Answer 9

yea.. real.. u urself gave the reason!

Answer 10

theer is no value of x then hw can u conclude dat there is no real solution

Answer 11

tkhunny.. u explain her oki

Answer 12

If t is Real, then t^2 is non-negative.
If x is Real, then x^2 is non-negative.
t^2x^2 is non-negative.
-t^2x^2 is non-positive.
-9-t^2x^2 is negative.

|x| is non-negative
-9-t^2x^2 is negative.

There is no Real Solution.

If there is a solution, we will have to invent some other sort of number with other sorts of properties.