Question

Plz help!!

A model rocket is launched from a platform and its height 'h' metres is given as a function of the elapsed time 't' seconds by h = -4.9^2 + 180t + 2. Determine the following:

a) The maximum height of the rocket
b) The time required for the rocket to reach its maximum height
c) the time required for the rocket to reach the ground

Answer 1

Are you allowed to use a graphing calculator?

Answer 2

If you can't, another way you can do this is doing the derivative and setting it equal to zero. Since the derivative tells the slope, and maximum occurs at a slope of 0. So find the derivative of the function and set it equal to zero.
\[-4.9t ^{2}+180t+2=-9.8t+180\]\[-9.8t+180=0 => -9.8t = -180 => t = 18.367\]This should give you a good start