In a group, the 80% is married. 75% of the married have a work. 5% does not have a work and are not marrid
What percentage does not have a work?
25% I think
|dw:1383266857976:dw| Is that right?
The last 25% is without
actually i got a different answer, we know this much 80% = married 75 % = married and work 5% = married and do not work from this we know that out of the 80% of the people, only 5% do not have a job. so now let look at the remaining 20% of non married people
we know this much 5% = people who arent married and do not work so far this is all be know from the info provided but the question doesnt mention anything about the remaining 15% but, we can reason out that the 15% much be people who are not married but work there fore 15% = not married but work
finally, out of the 80% of married people, only 5% do not have jobs and out of the 20% of single people only 5% do not have job. to conclude, there are a total of 10% of people that do not have jobs, 10% is ur answer
i am sorry that it was so long but i hope that you understood it, any questions?
But the problem says Married: 80% (of the total) With work: 75% (of the married, so this is 75% of 80, so it would be a 60% of the total) Without a work: 5% (of the total, so itwould be 25% of a 20%) Single: 20%
I am right until there?
|dw:1383269057108:dw|
Ok, perfect, so a 10% has no work
wait
But the 75% apply to the married people, so it is 75% of 80%, (60)
|dw:1383269250683:dw|
ok and the 5% does not have a work and are not marrid, is that 5% of 100%? or something else?
the quesiton doesnt specify if that 5% is of the 100% or the remaining 20%
"Finally, 5% are not married and neither have a work" I think it is of the 100%
i agree with you that it's 75% of 80%, ill change that now, but before i do, i would think 5% of 100% as well
yea i think it's 25% as well, sry for mis reading the question
but atleast u got a 2nd opinion in the end!
Hahaha thanks :)
The hard question is: if one person has a work, which is the probability of him being married
\[P(A\B) = \frac{ P(A intersecting with B)}{ B }\]
Is that useful for this one?
im not familiar with that equation, but ik you dont need it, it can be reasoned out
P(A)=3/4 (probability of being married P(B)= 3/4 (probability of having a job)
Mmm...75% of the 75%
or 75% of 60%
im a calc student so idk statistic equations lol but ik that i can reason it out lol 1 sec
id say 60% are married and work, 15% arnt married but work. there fore we find 60/75 x 100 and that should give us our answer
i got 80%
wait
Ok
yep i got 80%
Can you explain me again the logic? You want to calculate the 75% of the 60%, but why?
kk, i did it in a calculus way though xD but u seem smart enough to understadn it :) Let x = total number of people y = 75% of x (number of people working) and let z = 60% of x (number of people married and working) therefore z/y times 100 = the percentage of married and working compared to just working)
therefore z/y of 100 = 60% of x / 75% of x times 100 the x cancels so 60/100 / 75/100 times 100 60/75 times 100
if that makes sense xD
does that make any sense?
Yes :D thanks
The last question is what percentage is married inside the ones that does not have a job
So... 75-100 x-80 Can that apply? 80*75 divded by 100
I mean x-25
Let me formulate that again
x=total y=75% of x z=25% of x
75/25=3*
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