Question

find dy/dx 4(x-1)^3-2x^2y^3=5x^2

Answer 1

\[\Large 4(x-1)^3-2x^2y^3\quad=\quad 5x^2\]So we need to find dy/dx implicitly? :)
Did I copy the problem down correctly?

Answer 2

\[\Large \color{royalblue}{\left[4(x-1)^3\right]'}-\color{royalblue}{\left[2x^2\right]'}y^3-2x^2\color{royalblue}{\left[y^3\right]'}\quad=\quad \color{royalblue}{\left[5x^2\right]'}\]

So these are the derivatives we'll need to take, in blue.
The product rule was applied to the 2x^2y^3 term.
Understand that part? :o