Question

can someone please help me with these equations

Answer 1

\[\frac{ 4f^{6}g^{2} }{ 16g^{3} }\]

Answer 2

\[\frac{ x^{2}-36 }{ x^{2}-12x+36 }\]

Answer 3

i need to symplify them

Answer 4

\[\frac{4f ^{6}g ^{2}}{16g ^{3}}\]
I suggest that you divide the numerator and the denominator by 4g^2. Can you do that?

Answer 5

huh but there is no 4g^2

Answer 6

im sorry i dont understand

Answer 7

The numerator is 4f^6g^2. Can you see the term 4g^2 in the numerator?

Answer 8

and thank you @pradiv

Answer 9

yes

Answer 10

do they have to be close together?

Answer 11

No. 4f^6g^2 has exactly the same value as 4g^2f^6.

Answer 12

ok

Answer 13

So if you divide the numerator by 4g^2 what is the result?
\[\frac{4f^{6}g^{2}}{4g^{2}}=?\]

Answer 14

f^6?? cause the rest cancle the 4 and 4 cancel and the g^2?

Answer 15

Good work!! Now looking at the denominator and dividing it by 4g^2, what is the result?
\[\frac{16g^{3}}{4g^{2}}=?\]

Answer 16

4 because g^2 cancels ?

Answer 17

You are correct that the 4 cancels. However g^3/g^2 = g. Do you follow?

Answer 18

oh sorry i thought that said g^2 on both

Answer 19

No worries. So we have found that the expression can be simplified to give the following:
\[\frac{4f^{6}g^{2}}{16g^{3}}=\frac{f^{6}}{4g}\]

Answer 20

ok got it

Answer 21

Well done :)

Answer 22

thank you so much

Answer 23

You're welcome :)

Answer 24

if i have anymore can i tag you on a new one? or mail you ? anything that suits u better

Answer 25

You can tag me if I'm logged in :)

Answer 26

ok thanxx :)