one more . What is the derivative of f(x) = ln(x^e +e^x)
The derivative of ln (u) = (i/u)(du) or du/u So the derivative will be (1/(x^e + e^x)) (ex^(e-1) + e^x)
\(\sf \color{}{\frac{1}{x^e+e^x}(e^x)}\)
Oops, forgot the \(\sf \color{}{ex^{e-1}}\)
can you walk thru the steps a bit
U is (x^e + e^x)
The derivative will be 1/u or 1/(x^e + e^x) multiplied by the derivative of u. The derivative of u is the derivative of (x^e + e^x). The derivative of x^e is tricky...it is like x^constant..since e is a constant. so the derivative of x^e is ex^(e-1); and the derivative of e^x is e^x. Think of x^e like x^4. The derivative of x^4 is 4x^(4-1) or 4x^3. Similarly, the derivative of x^e is e(x^(e-1)).
Makes sense?
you are awesome... got it.. thanks
Very welcome.
The tricky part is the part when you need the derivative of x^e. Many students will get that part wrong.
It should be crystal clear that the derivative is e(x^(e-1)).
so if you solve for f'(1) what would you get?
Lets see...you would subsitute x = 1 into the derivative, and you'll get.......
(1 + (1/e)) (2e) or 2e + 2 or 2(e+1). Agree?
I got 2e/e+1
Let me double-check....
My answer is correct...let's do it together. 1^e = 1 e^1 = e 1^(e-1) = 1
Agree?
1^(e-1)=1?
1^any number = 1 e-1 is just a number
ok
true..
we are goo
good
so do the arithmetic again carefully..you will see my answer is correct. If you still dont have what I got, then we will have to work it step-by-step
its fine... thenks
poor spelling
Is it fine? Are you 100% convinced that f ' (1) = 2(e+1)???
we have an e^e-1 what is this simplified to
thats 0...because x^a multiplied by x^b = x^(a+b) so e^1 times e^(-1) = e^0 = 1
add the exponents.
e is the base;
one exponent is 1; the other exponent is -1; 1 + (-1) = 0 e^0 = 1 any number to the 0 power = 1.
but its not that... it is e-1 so actually 1.7
e^e-1
e(x^(e-1)) means you do x^(e-1) multiplied by e
just like 4x^3 means x^3 multiplied by 4
You are putting in x = 1, so e(x^(e-1)) = e(1^(e-1)) = e(1) = e
so than it would be 2e on the numerator
agree...and the denominator, you get what?
e+1
agree...so you get (2e/(e+1)) ...you are correct..I must have made an arithmetic error along the way.
it happens.. thanks
With so many x's and e's..some error may occur if not extra careful.
I am aware
Good luck.
But, you know something...on an exam..such an error, MAY result in a 1-point loss...as thats a careless arithmetic..whats important is the calculus.
multiple choice test answers... worse
Of course, we want the exact value of f ' (1).
True...but I cant believe such a multiple-choice question asking for f ' (1). No professional exam would include this question asking for f ' (1). The derivative, yes...not f ' (1).
We want to know if the student knows the calculus; not if they will make a careless arithmetic error.
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