7-9) A 10 kg object (m1) initially moving to the right at 20 m/s makes a totally elastic head on collision with a 15 kg object (m2) which was initially moving to the left at 5 m/s. Find the final velocities of each object. HINT: Treat this as a one-dimensional problem.
Answer is V1F: -10m/s and V2F: +15 m/s. Can someone explain this please? Thanks.
Define elastic? I would use the formula \[F = ma\]and then use the resulting info to find velocity. Also: \[a = \frac{ \Delta v }{ t } = \frac{ v }{ t }\]and this one: \[a = \frac{ F }{ m }\]
I borrowed the bottom two formulas from @Lessis so I get no credit for those. xD
An elastic colission is a colission that conserves energy and momentum. So, that means that before and after the colission, the momentum and energy are equal.
Ah. Makes sense
They bounce back like elastic balls loose no kinetic energy.
lol, I'd help you if I knew how.
LOL. Thanks for the "want to help me" XDDDD
Maybe once I have more knowledge on this subject, then I'll be able to help more people.
Well, of course. but I'm no help here what w/ the elastics, so @Lessis can help you more :)
See you on my other question XD
Before the collision, the total momentum (The sum of the momentum of each particle) is the same as after. So: \[p _{1,1}+p _{2,1}= p _{1,2}+p _{2,2}\] You also have the same thing happening for the kinetic energy, since your potential energy is 0 (They're both on the ground). So: \[k _{1,1}+k _{2,1}= k _{1,2}+k _{2,2}\]
...why am I getting notifications on this....
Notice that this only happens because your collisions are elastic, in inelastic collisions, some of your energy is lost (Due to heat, sound, etc).
I think that makes sense. Thanks Lessis. @kittiwitti1 , once I close it, you won't be bothered anymore by this. Thank guys for you help. Appreciate it.
Just remember, you have two velocities to get, and two equations to get them from, so you have to solve the system to get the answer. Good luck!
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