A businessman models the number of items (in thousands) that his company sold from 1998 through 2004 as N(x) = -0.1x³ + x² - 3x + 4 and the average price per item (in dollars) as P(x) = 0.2x + 5, where x represents the number of years since 1998. Write a polynomial R(x) that can be used to model the total revenue for this company.
I think revenue is the money coming in, which is the number of items sold times the cost per item. so R(x)= P(x)*N(x) they probably want you to multiply it out.
So it would be: R(x) = (0.2x + 5)(-0.1x³ + x² - 3x + 4) @phi
yes.
Okay! I can do that!
so then \[R(x) = -0.02x^4-0.3x^3 + 4.4x^2 -14.2x\] ???
@phi did I get it right?
to multiply out (0.2x + 5)(-0.1x³ + x² - 3x + 4) you would do 0.2x(-0.1x³ + x² - 3x + 4) + 5(-0.1x³ + x² - 3x + 4) distribute the .2x on the first term, and 5 on the 2nd combine "like terms" what do you get for the first part: 0.2x(-0.1x³ + x² - 3x + 4)
\[-0.02x^4 + 0.2x^3 - 0.6x^2 + 0.8x + 0\]
yes, now the 2nd term, distribute the 5 5(-0.1x³ + x² - 3x + 4)
it looks like your original answer is correct except it is missing the last term.
And then the second is \[-0.5x^3 +5x^2 - 15x + 20 \]
yes, now combine them. You get what you had, except for a 20 you left off, the first time.
So what I get is: \[0.01x^7 - 0.2x^6 + 1.6x^5 - 6.8x^4 + 17x^3 - 24x^2 + 16x \]
I multiply them together right?
no, you add them
.... Okay, my mistake! Hold on one sec
you already multiplied them, now you are simplifying
That makes more sense So now I get\[R(x)=−0.02x^4−0.3x^3+4.4x^2−14.2x + 20\]
yes, looks good
AWESOME!!!!! Thank you so much!
yw
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