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How to find the dervative of y=x^ln(x)
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take log both side ln y= lnx *lnx ln y= (ln x)^2
now differntiate
(1/y)*dy/dx = 2* (ln x )*1/x dy/dx=y*(2/x)* (ln x ) but y=x^ln(x) so dy/dx = x^ln(x) * (2/x)* (ln x )
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