Question

Check my work?

Answer 1

luigi0210 can u help me @Luigi0210

Answer 2

Find y'
\[\LARGE y^3+y^2-5y-x^2=-4\]
\[\LARGE \frac{d}{dx}(y^3+y^2-5y-x^2)=\frac{d}{dx}(-4)\]\[\LARGE (3y^2y'+2yy'-5y'-2x)=0\]
Right so far?

Answer 3

@Luigi0210

Answer 4

correct! :)

Answer 5

yep

Answer 6

So finishing it off:
\[\LARGE y'(3y^2+2y-5)=2x\]
And
\[\LARGE y'=\frac{2x}{3y^2+2y-5}\]

Answer 7

you're good at this.
accept it. -.-

Answer 8

@hartnn

Answer 9

Haha, not really hartnn, just reviewing at the moment

Answer 10

what hartnn said lol