Question

Find the product of the complex number and its conjugate.
1 + 3i

Answer 1

recall that \(\bf \large (a-b)(a+b) = a^2-b^2\)

Answer 2

for making o
conjugate just convert i to -i so:
1+3i --> 1-3i
(1+3i)(1-3i)=..

Answer 3

its conjugate is
1 - 3i
and the product of it is
(1=3i)(1-3i)=1-(3i)^2

Answer 4

1 + 9i

Answer 5

(1-3i)(1+3i)=1+3i-3i-9(i^2)=1+9=10
because i^2=-1

Answer 6

1-9(-1) since i^2=-1
1+9=10
that is