[9.01] Identify the vertex for the graph of y = −3x2 − 6x + 4.

(1, 13)

(−1, 13)

(1, 7)

(−1, 7)

Question

[9.01] Identify the vertex for the graph of y = −3x2 − 6x + 4.

 (1, 13)

 (−1, 13)

 (1, 7)

 (−1, 7)

anonymous · Answer

there are two ways I can think to solve this, each depend on what math class you are in, algebra or calc?

anonymous · Answer

algebra

jdoe0001 · Answer

for a parabola equation like $\bf ax^2+bx+c$ you can find the the vertex at the coordinates of $\bf \left(-\cfrac{b}{2a}\quad ,\quad  c-\cfrac{b^2}{4a}\right)$

anonymous · Answer

ok

anonymous · Answer

y=-3x^2-6x+4
y=-3(x^2+2x)+4                 Factor -3
y=-3(x^2+2x+1)+4+3        Complete square
y=-3(x+1)^2+7
vetex (-1,7)

anonymous · Answer

Oh ok so its D

anonymous · Answer

Yes

anonymous · Answer

thank you can you help me on this [9.01] What is the value of the coefficient "b" when the quadratic equation y = (3x + 2)(2x − 1) is written in standard form?

 −7

 −2

 1

 6

anonymous · Answer

will it be -7

anonymous · Answer

its not -7, 
foil the equation and you'll see what 'b' becomes

anonymous · Answer

No its not -7 its 1 http://openstudy.com/study#/updates/50719bbfe4b0c2dc8340dcb1 Where I found the answer

anonymous · Answer

y = (3x+2)(2x-1)
y = 6x^2 +4x -3x - 2
y = 6x^2 +x -2
y = ax^2 +bx + c

anonymous · Answer

It was easy I just over thought it