Question

[9.01] Determine whether the graph of y = x2 + 2x − 8 has a maximum or minimum point, then find the maximum or minimum value.

Maximum; (-1, -9)

Minimum; (-1, -9)

Maximum; (-9, -1)

Minimum; (-9, -1)

Answer 1

do you know how to put it into vertex form? that's how i'd start

Answer 2

No i get mix up

Answer 3

wat up white trash

Answer 4

@Felicia123

Answer 5

????

Answer 6

retrice?????

Answer 7

thats mean

Answer 8

but true

Answer 9

truth hurts

Answer 10

your mess up

Answer 11

wright right

Answer 12

MESS

Answer 13

??????

Answer 14

k so to put it into vertex form:
y = x2 + 2x − 8
(x^2+2x)-8
take the middle term and divide it by 2, then square it, to get the last term.
(x^2+2x+1-1)-8
move the negative one out of the brackets:
(x^2+2x+1)-9
factor the newly formed perfect square trinomial!
y= (x+1)^2-9
-1 is the x term of the vertex
-9 is the y term of the vertex
the coefficient (a) is 1, which is positive, so the parabola opens upwards :)

Answer 15

so its A

Answer 16

therefore the vertex is a minimum and the answer would be B!

Answer 17

Oh ok

Answer 18

because a parabola that opens upwards looks like this, with a vertex that's a minimum

Answer 19

ur retarded