HELP PLEASE FOR PART B URGENT?? (a) From a stack of 3 dice, one is taken and rolled twice. If, unknown to the gambler, one of the dice is weighted and has a 1/8 chance of rolling a 6, what is the probability that the gambler rolls two 6's? (b) If the gambler has rolled two sixes, what is the probability that he has rolled the weighted die?
Hints: The Probability of selecting the weighted die is 1/3 The Probability of rolling a 6 on the first roll with the weighted die is 1/8 The probability of rolling a 6 on the second roll with the weighted die is 1/8
so i multiply the three and get 1/192
then i divide it by my answer in part a and get (1/192)/(41/1728) to get an answer of 9/41?
@Hero is that correct?
i knew this seemed familiar ... http://openstudy.com/users/amistre64#/updates/52727183e4b077aaee843484
why do you edit out the content of your queston?
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