Write an equation of a line that passes through (9,-5) and (3,-5).
first find the slope of this line, do you know how to do that?
\[\frac{y_1-y_2}{x_1-x_2}=slope\]
plug in your points into (the above) slope formula.
\(\begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &(9\quad ,&-5)\quad &(3\quad ,&-5) \end{array} \\\quad \\ \large slope = m= \cfrac{rise}{run} \implies \cfrac{y_2-y_1}{x_2-x_1} \\ \quad \\ \bf y-y_1=m(x-x_1)\quad \textit{plug in your values to get the equation}\)
@cuitiefromthesouth2, we need your cooperation to help you, we can't just do your work, please say something.....
sorry I was trying to work out the problem
Oh, go a head and work in here PLEASE! We will correct you if your wrong.
okay
m=-5-(-5)/3-9
=0/6
0/-6
cuitiefromthesouth2, the other way, not -5-(-5)/3-9, IT IS 3-9/-5-(-5)
=-6/0
yep! The slope is undefined and REMEMBER: if slope is undefined the line is vertical, because in (any) vertical the x coordinates are all same. lets take a vertical line|dw:1383426226547:dw|
See?
yea , thank you
yes
So how would you write the equation of your line?
In my example the equation would be x=a, what about your's?
3-9/-5-(-5) = -6/0, which is undefined ?
@SolomonZelman
yes, so it is x=-6|dw:1383427524383:dw|
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