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use the change of base theoremto evaluate round to two decimal places. log7^60
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same question is asked (and being answered) right here: http://openstudy.com/study#/updates/52741b37e4b0bd59f4c02019
anybody know how to solve it ??
....
sorry I was a bit caught up \(\bf \textit{log change of base }\quad log_ab=\cfrac{log_cb}{log_ca}\) the "c" value could be anything, it just have to be the same top and bottom, so of course the common ones will be log base 10 \(\bf log_{10}\ or \ ln\) or natural logarithm, thus \(\bf log_760\implies \cfrac{log_{10}60}{log_{10}7}\)
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