What is the cubic function with these four points: (2,5)(3,7.2)(6.3,7.8)(9,10.7)?
You can represent a cubic equation in the form \(y = ax^3 + bx^2 + cx + d\) By plugging the four sets of coordinates you're given into x and y, you can get four linear equations, which you can solve to find a, b, c, and d. Do you follow?
yeah ive gotten that far i dont know how to find a b and c
and d
The same way you solve any other system of linear equations.
What are your equations?
you use the template of \(\bf y=ax^3+bx^2+cx+d\) and use each point (x, y) values to obtain 1 equation you have 4 points, thus 4 equations, and you'd end up with a system of equations of 4 variables, then you'd eliminate to find the values
5=8a+4b+2c+d 7.2=18a+9b+3c+d 7.8=250.05a+39.69b+6.3c+d 10.7=729a+81b+9c+d
Ok, so I wouldn't waste time messing around and just use matrices, unless you're supposed to crunch this out manually for some reason.
i dont know how to use matrices
\[\left[\begin{matrix}8 & 4 & 2 & 1 \\ 18 & 9 & 3 & 1 \\ 250.05 & 39.69 & 6.3 & 1 \\ 729 & 81 & 9 & 1\end{matrix}\right]\left[\begin{matrix}a \\ b \\ c \\ d\end{matrix}\right] = \left[\begin{matrix}5 \\ 7.2 \\ 7.8 \\ 10.7 \end{matrix}\right]\]
Which means \[\left[\begin{matrix}a \\ b \\ c \\ d\end{matrix}\right] = \left[\begin{matrix}5 \\ 7.2 \\ 7.8 \\ 10.7 \end{matrix}\right]\left[\begin{matrix}8 & 4 & 2 & 1 \\ 18 & 9 & 3 & 1 \\ 250.05 & 39.69 & 6.3 & 1 \\ 729 & 81 & 9 & 1\end{matrix}\right]^{\huge-1}\]
Don't ask me how to take the inverse of a 4x4 matrix. Calculators are good at it.
okay
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