Question

lim
x-->0
f(x) = (e^x - 1)/(sin x)
= 0/0
L'hopital's rule

Answer 1

\[f(x) =\frac{ (e^x-1)' }{ (sinx)' }\]

Answer 2

l'hospital rule states that if you have a lim that's 0/0 you can use f'x/g'x to get the limit

Answer 3

l'hospital rule states that if you have a lim that's 0/0 you can use f'x/g'x to get the limit

Answer 4

\[\frac{ e^x }{ \cos~x } = \frac{ e^0 }{ \cos 0 } = 1\]
right? @Luigi0210

Answer 5

1/1=1
is right

Answer 6

That's right

Answer 7

thanks

Answer 8

welcome!