Question

yo my real niqq3r
@Luigi0210 and my niqer @awkwardpanda

Answer 1

XD "niqer"

Answer 2

okie bud lets start .

Answer 3

we left off at factoring yesterday for finding limits.

Answer 4

yus :3

Answer 5

let's see if you held the info.
evaluate the limit
\[\lim_{x \rightarrow 2} \frac{ 2x^2 - 3 }{ x + 5 }\]

Answer 6

\[\frac{ 2(2)^2-3}{ 2+5 }\]

Answer 7

yer

Answer 8

simplify

Answer 9

okai

Answer 10

7? >.>

Answer 11

\[\frac{ 5 }{ 7 }\]...

Answer 12

DENG IT it's the simple things that i forget ;-;

Answer 13

ok, you can do that later, first lets learn about discontinuities and then the conjugation method

Answer 14

okay :3

Answer 15

do you know how to find the domain of a rational function?
or a function in general?
this is a rational function
\[f(x) = \frac{ x^2 - 5 }{ x+5 }\]

Answer 16

could you remind me pls .-.

Answer 17

ok, so you don't know..
let's start with the rational function..
you set the denominator to equal zero
and solve ..
\[x + 5 = 0\]
x = -5

the domain is all real numbers except -5, because the denominator becomes 0 and you can't divide by zero.
\[[D: \mathbb{R} : x \ne -5]\]

Answer 18

well that's not the correct notation for writing domain but w/e ill do that later.

Answer 19

its something like that i forget.

Answer 20

i get it, in a way XD

Answer 21

anyways -5 is the domain , the vertical asymptote where this function does not touch


the graph never touches -5