Question

What is the simplified form of the following:

Answer 1

\[\frac{ \frac{ x^2-1 }{ 9x } }{ \frac{ x^2+2x+1 }{ 3x^2 } }\]

Answer 2

@hba @nincompoop

Answer 3

I cant see equation right D:

Answer 4

.

Answer 5

I'll draw it for you... Hold on please! :)

Answer 6

Wow that is a hard one aint it XD @ranga

Answer 7

(x^2 - 1) = (x + 1)(x - 1)
x^2 + 2x + 1 = (x + 1)^2
You can put those two factors and simplify then simplify the problem.

Answer 8

I don't understand how to simplify that...

Answer 9

you'd factor the numerators mainly

Answer 10

and keep in mind that \(\bf \cfrac{\quad \frac{a}{b}\quad }{\frac{c}{d}}\implies \cfrac{a}{b}\cdot \cfrac{d}{c}\)

Answer 11

{ (x^2 - 1) / 9x } / { (x^2 + 2x + 1) / 3x^2 } =
(x^2 - 1) / 9x * 3x^2 / (x^2 + 2x + 1) =
(x + 1)(x - 1) / 9x * 3x^2 / (x + 1)^2 =
(x + 1)(x - 1) / (x + 1)^2 * 3x^2 / 9x =
You can try to simplify from here.

Answer 12

so we'd have (x-1)/(x+1) * (3x^2)/9x?

Answer 13

the second part would be x^2/3x after simplifying, right?

Answer 14

the second part you can cancel x too.

Answer 15

so the final answer would be \[\frac{ x(x-1) }{ 3(x+1) }\]?

Answer 16

Thank you sooooo much!!!

Answer 17

you are welcome.

Answer 18

Do you think you could help me with a couple more if I post them?