limx→0 14csc^2(x)−14cot^2(x) using L'Hopital's rule..

Question

limx→0 14csc^2(x)−14cot^2(x)  using L'Hopital's rule..

anonymous · Answer

have you used l'hopital's rule before when the equation is subtraction?

anonymous · Answer

no

anonymous · Answer

awh, ok thats why this is being a pain for ya!

anonymous · Answer

can you walk me through the steps of how to complete this problem?

anonymous · Answer

yes, 1 second..

anonymous · Answer

its been a while since i've done one like this but...
this type of problem is called 'indeterminate differences'
so the trick is to get a common denominator. (hint, first start with re writting the csc and cot as sin and cos)
can you do this, or should i help u more?

anonymous · Answer

so it will be rewritten as 14/sin^2x -14/tan^2x?

anonymous · Answer

good, then lets convert the tan into terms of sin and cos

anonymous · Answer

how to do that?

anonymous · Answer

|dw:1383350534863:dw|
does that make sense where things go? I left out the 14 and ^2