Question

Find the equation of tangent to the curve for y=-3x^2+5x+3

Answer 1

what class is this for, calculus?

Answer 2

yes it is calculus

Answer 3

it's asking for the derivative do you know how to take the derivative yet?

Answer 4

so the derivative is-6x+5

Answer 5

yes

Answer 6

i dont know what to do after that

Answer 7

what form do they want the answer in? did they give you a point on the curve?

Answer 8

the problem says for the curve equation y=-3x^2+5x+3, find equation of tangent to the curve

Answer 9

part b of the problem is find the slope of the tangent at x=3

Answer 10

part c of the aproblem is to find the angle of inclination of the tangent

Answer 11

ok the answer to part a is the derivative and for part b put in 3 for x and solve for y

Answer 12

am i putting the 3 into the original equation or the derived equation

Answer 13

once you have the answer for part b take the arctan of that and it will give you the angle

Answer 14

into the tangent function which is the derivitive

Answer 15

so its -6(3)+5 correct and three fore i should get a slop of 13....
thta seems like an awfully high slope

Answer 16

y' is the slope at any point x along the curve. so if you want the slope at x=3 replace x with 3 and solve. if tou want the tangent at x=189 put in 189 for x and solve.

Answer 17

i mean -13

Answer 18

it dosen't matter really, that will equate to -85.6°

Answer 19

ok thank you

Answer 20

If part a is to find the equation of the tangent line, then we aren't totally complete on the answer.
You found the formula for the slope of the tangent line at any point on the curve.
Linear functions can be written in this form: y-y1=m(x-x1)
Say we want to find the tangent line at (a,f(a))
then y=m(x-a)+f(a)
Don't forget to replace your m here with y' evaluated at x=a.

Answer 21

I am confused again...would you be able to explain and show the steps to each part