Question

Help please

Answer 1

With?

Answer 2

ill help you if you help me i promise
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Answer 3

I'm pretty bad at math is why i need help, sorry

Answer 4

If you simplify the expression under the radical you'd get (1-cos^2(theta))

Does that seem familiar to you?

Answer 5

not at all, i had no clue what was happening at all during this unit

Answer 6

Here maybe this'll help jog your memory :p
\[\sin ^{2}(x) + \cos ^{2}(x) \]

Answer 7

Yeah still no clue /:

Answer 8

\[\sin ^{2}(Θ) + \cos ^{2} (Θ) = 1\]
\[\sin ^{2}(Θ) = 1-\cos^{2}(Θ)\]

Answer 9

well its like -1 cos and +1 cos so it would come out to be the sqrt of just cos I dont know

Answer 10

You have the right idea... kinda
(1-cos Θ)(1+cosΘ) = 1 - cosΘ + cos Θ - cos^2(Θ)
and then the cos(Θ)'s cancel out so you're left with\[\sqrt{1-\cos^{2}Θ}\]

Answer 11

which = sin?

Answer 12

god this stuff is so confusing

Answer 13

I've been in the same boat as you. To be honest, all you can do to clear the confusion is read the material. Do problems. Get help. Do more problems.

If you go back to your basic pythagorean identity
\[\sin ^{2}(Θ) + \cos^{2}(Θ) = 1\]
and subtract cos2(Θ) from both sides, you get \[1-\cos^{2}(Θ) = \sin^{2}(Θ)\]

Remember how square roots work?\[\sqrt{x^{2}} = x\]

Answer 14

I remember square roots, i have just been lost sense the start of this unit I don't understand any of it

Answer 15

\[\sqrt{1-\cos^{2}(Θ)} = \sqrt{\sin^{2}(Θ)} = \sin(Θ) \]
recall that when you take the square root you add a \[\pm\]

Answer 16

I'll gladly help you out with anything you're struggling with. Trig can be tricky

Answer 17

My goodness, it's like a different language D';

Answer 18

eventually you'll have seen the different problems that can be asked. You only have so many different tools to use too.

There are basic things that you'll need to memorize before you approach problems, but as I said I can step ya through it (hopefully I still remember this)

Answer 19

Okay :3 well thank you for your help