Question

Algebra II help!

Answer 1

@shamil98

Answer 2

Factor the equations first then flip the second one (reciprocal) and multiply and cancel out the terms that are repeating.

Answer 3

Looks like a quadratic factoring fest!

Answer 4

I factored the first one and got \[\frac{ (y-4)(y+3) }{ (y-4)(y-2) }\]

Answer 5

the y-4 should cancel so I'm left with y+3/y-2, right?

Answer 6

good. now cancel the terms, yes! good job :)

Answer 7

and now factor the second one remember to flip it.

Answer 8

when I factored the second one, I got \[\frac{ (y+5)(y-3) }{ (y-5)(y-2) }\]... but nothing cancels.... Did I do something wrong?

Answer 9

\[\frac{ y+3 }{ y-2 } \times \frac{ (y-5)(y-2) }{ (y+5)(y-3) }\]

Answer 10

the (y -2)'s cancels

Answer 11

what are you left with ?

Answer 12

\[y+3 \times \frac{ y-5 }{ (y+5)(y-3) }\]?

Answer 13

\[\frac{ (y+3)(y-5) }{ (y+5)(y-3) }\]

Answer 14

yep

Answer 15

so is that the final answer?

Answer 16

you can't reduce it anymore so yes .

Answer 17

@shamil98 I have two more if you don't mind helping with them....