Question

-

Answer 1

L×W = 48
L = 3W

This implies that
3W×W = 48
3W²=48
W²=16
W=4

Plugging that into our first equation:
L×4 = 48
L = 12

So now we have the outer perimeter of our field:

Answer 2

where is the 12 coming from, 4x3? the questin never gives a width measurement which is where im confused

Answer 3

A rectangle has an area of 48m^2. The length of the lot is three times the width.
If the length is L and the width is W, we have two equations we can work with.

Area = 48m² = length times width = L×W
The length is three times the width → L = 3W
Substituting 3W for L in the first equation, we find:
48m² = (3W)×W
48m² = 3W²
16m² = W²
4m = W

We can then use that value for W in one of the original equations:
L = 3W → L = 3(4) → L = 12

Answer 4

ok ty

Answer 5

so i understand that portion, how do i form the equation?