Question

A messy Integral,

What is he doing here?

Can you help me solve this ?
http://screencast.com/t/0CtKjlhYqbEW

Answer 1

If you integrate that integrand (4at^2 -Bt)

\[\frac{1}{3}4\alpha t^3 -\frac{1}{2}\beta t^2\]
from \[t = 0 -> t=\frac{\beta}{4\alpha}\]

Answer 2

can you help me integrate it

Answer 3

We Do Not Inforce cheeting @Christos Please look at the terms and conditions . I will be banning you IP address from now on. Have A Wonderful Night and remember Cheating is never the way!

Answer 4

you can pull out the 4a-b and then just integrate t²-t

Answer 5

it's called che"a"ting and who are you now ?

Answer 6

I'm on my way to being one of the administrators on here I have to point out when someone is che"a"ting

Answer 7

Do I look like I care ? please tell me if I look like I care

Answer 8

I am just asking for the steps not the solution xd thanks

Answer 9

Okay , I'm in the process of banning your IP Address no more cheating here . That goes for you will no longer have an account or be able to create an account. Have a wonderful night , #1 rule on Open Study Is No Cheating!

Answer 10

Your funny , no you aren't :D

Answer 11

Lol you got me , I wouldn't be the one to talk ,

Answer 12

;p

Answer 13

\[\int\limits_{0}^{\beta/4*\alpha}(4*\alpha*t ^{2}-\beta*t)dt=4*\alpha (\int\limits_{0}^{\beta/4*\alpha}t ^{2}dt)-\beta(\int\limits_{0}^{\beta/4*\alpha}tdt)\]
now simply integrate the two different simple integrals with given limits.
It finally comes out \[-(\beta^3/96*\alpha^2)\]
THE dot dot thing is simply the procedure which is not written overthere so it is mentioned by (.......) .That means there is a procedure before the answer.Thats it.