Please Assist Calculating Inflation Rate See Attachment
% a year = % a month x 12 months a year
just reverse the concept for % a month...
is it 7.2%?
yup... 0.6% x 12 = 7.2%
okay thanks. What abut the second equation?
question*
as i said... reverse the concept... :)
It says that those answers are incorrect @Orion1213
Got a formula inthis website... http://www.algebra.com/algebra/homework/word/age/Age_Word_Problems.faq.question.622296.html
ok, I will try it
for the rate.... (1 + r) ... is an annual rate...
... t is in year
okay
from here quote.... Annualizing the Rate of Inflation Formula As with annualizing any monthly rate, the monthly rate of inflation can not be annualized by simply multiplying it by 12, as this does not consider compounding. The same concept can be applied to adding each monthly percentage change in the consumer price index as an attempt to find the annual percentage change in the consumer price index. The proper way to calculate the annual rate of inflation is to use the year's initial and ending CPI in the formula.
what would C be? I know that it represents the initial price but what would it be based on the given information?
Can you try 7.4% for a) and see if it is correct. If it is I can tell you what I did. If not I will just go away.
well I only get three more tries at the answer so if I plug an answer in for a) then I also have to do it for b)
Let me use the same method and calculate b. Hang on.
a) 7.4% b) 0.5%
they were both right. Thank you. How did you do it?
Good. I read the quote from Orion1213 above: ".... the monthly rate of inflation can not be annualized by simply multiplying it by 12, as this does not consider compounding." So the monthly rate has to bee compounded 12 times to get the yearly rate. So I modified the formula we use in calculating compound interest for this situation: (1 + r_yearly) = (1 + r_monthly)^12 r_yearly is the yearly rate of inflation and r_monthly is the monthly rate of inflation.
For part a), r_monthly = 0.006, calculate r_yearly For part b), r_yearly = 0.06, calculate r_monthly
(1 + r_yearly) = (1 + r_monthly)^12 part a) (1 + r_yearly) = (1 + 0.006)^12 = 1.006^12 = 1.074 r_yearly = 1.074 - 1 = .074 or 7.4% part b) (1 + 0.06) = (1 + r_monthly)^12 (1 + r_monthly)^12 = 1.06 take logs on both sides: log{ (1 + r_monthly)^12 } = log(1.06) 12 * log(1 + r_monthly) = log(1.06) log(1 + r_monthly) = log(1.06) / 12 = 0.00211 Raise both sides to the power of 10 to cancel out logs (1 + r_monthly) = 10^(0.00211) = 1.0049 r_monthly = 1.0049 - 1 = 0.0049 = 0.49% rounded to the first decimal it is 0.5%
... i learned also... :)
Okay thank you @ranga and @Orion1213
you are welcome.
Starting with (1 + r_yearly) = (1 + r_monthly)^12 we can rewrite the equation with just r_yearly on the left hand side for part(a): r_yearly = (1 + r_monthly)^12 - 1 For part b) I realized it would be a lot easier to rewrite the first equation with r_monthly on the left hand side: (1 + r_yearly) = (1 + r_monthly)^12 (1 + r_monthly)^12 = (1 + r_yearly) Take 12th root on both sides (that is, raise it to power 1/12): 1 + r_monthly = (1 + r_yearly) ^ (1/12) r_monthly = (1 + r_yearly) ^ (1/12) - 1
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