Mathematics
12 Online
OpenStudy (luigi0210):
@shamil98
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OpenStudy (luigi0210):
Here is your problem:
\[\LARGE x^2+xy-y^2=4\]
OpenStudy (shamil98):
x^2 + xy - y^2 = 4
2x + y' - 2yy' = 0
?
OpenStudy (luigi0210):
Correct so far, finish it
OpenStudy (shamil98):
yay.
y'(1-2y) = -2x
y' = -2x/(1-2y)
?
OpenStudy (bibby):
how is xy y'?
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OpenStudy (shamil98):
x' = 1
y'=y'
1(y')=y'
OpenStudy (bibby):
I thought product rule meant xy = u'v + uv' = y + xy'
OpenStudy (luigi0210):
This isn't product rule though :P
OpenStudy (shamil98):
so luigi am i rite?
OpenStudy (luigi0210):
Wait.. is it?
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OpenStudy (shamil98):
well you differentiate each term by itself. it could be o.o
OpenStudy (luigi0210):
Crap, I think bibby is right..
OpenStudy (bibby):
wolfram says it's y
OpenStudy (luigi0210):
According to my work from a year ago.. I used product rule too..
OpenStudy (anonymous):
easy problem
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OpenStudy (shamil98):
x^2 + xy - y^2 = 4
2x + y + xy' - 2yy' = 0
ok.
y'(x-2y) = -2x-y
y' = (-2x-y)/(x-2y)
OpenStudy (anonymous):
Yes you have to use product rule
OpenStudy (anonymous):
for xy
OpenStudy (bibby):
I got the second one shamil got using the product rule
OpenStudy (luigi0210):
Sham, you have the same answer that's on my one year old paper c:
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OpenStudy (shamil98):
yay
OpenStudy (anonymous):
yay
OpenStudy (bibby):
third ^
OpenStudy (shamil98):
who do i give a medal to
OpenStudy (shamil98):
.-.
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OpenStudy (anonymous):
Batman
OpenStudy (luigi0210):
xD
OpenStudy (shamil98):
hmmmmmmmmmm
OpenStudy (shamil98):
everyone give those without a medal a medal :D
OpenStudy (shamil98):
luigi u give bib 1, bib u give lui 1
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OpenStudy (luigi0210):
batman can have the medal, but I want metal ;)
OpenStudy (luigi0210):
I prefer Au ;)
OpenStudy (anonymous):
Now do this problem, \[x^2-xy^2+y^4+^4y^2-sinx-cosx+\frac{ x^5-xy }{ y^2x }\]
OpenStudy (anonymous):
=3
OpenStudy (anonymous):
I just made it up :c
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OpenStudy (shamil98):
=3 as in the face? or equals 3
OpenStudy (luigi0210):
*shoots self*
OpenStudy (bibby):
Is this how communism would work?
OpenStudy (shamil98):
LOL
OpenStudy (anonymous):
Mhm sham i'll give ya a problem, hold on.
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OpenStudy (shamil98):
start a new question .-.
OpenStudy (anonymous):
I will
OpenStudy (shamil98):
dis one is solved.
OpenStudy (anonymous):
I'M BATMAN I KNOW EVERYTHING
OpenStudy (luigi0210):
batman, that plus sign has an exponent.. WHAT DOES IT MEAN?
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OpenStudy (anonymous):
A mistake
OpenStudy (anonymous):
lolol
OpenStudy (shamil98):
ITS THE BAT SIGNAL LUIGI
OpenStudy (shamil98):
its the secret code o.o
OpenStudy (luigi0210):
i c