Question

Choose the slope-intercept equation of the line that passes through the point shown and is perpendicular to the line shown.

Answer 1

y = two fifthsx + 1

y = -five halvesx - twenty-seven halves

y = -two fifthsx - 3

y = five halvesx + twenty-three halves

Answer 2

since u have a figure... you can determine the equation of the given line.... some points are visible already... standard form of line equation...
\[Ax + By + C = 0\]

Answer 3

in slope-intercept form:
\[y = -\frac{ A }{ B }x - \frac{ C }{ B }\]

Answer 4

the perpendicular line will have a standard form...
\[Bx + Ay + D = 0\]

Answer 5

the slope-intercept form....
\[y = -\frac{ B }{ A }x - \frac{ D }{ A }\]

Answer 6

... and this line contains the point mentioned in the problem...

Answer 7

... that will lead u to right answer...

Answer 8

i am so confused. :$

Answer 9

ok let us get the equation of the given line... obvious points are (0,2), (2,7), (-3,-1)...

Answer 10

to check, solve for the slope is constant at chosen obvious points... let P1(2,7), P2(0,2), P3(-3,-1)...
\[m = \frac{ (2 - 7) }{ (0 - 2) } = \frac{ -5 }{ -2 } = \frac{ 5 }{ 2 }\]

Answer 11

another 2 points to make sure...
\[m = \frac{ (-3 - 2) }{ (-2 - 0) } = \frac{ -5 }{ -2 } = \frac{ 5 }{ 2 }\]

Answer 12

correction for P3, it should be (-2,-3)... not (-3,-1)

Answer 13

so for the given line, the slope \[m = \frac{ 5 }{ 2 }\]

Answer 14

using slope-intercept form...
\[y = \frac{ 5 }{ 2 }x + 2\]

Answer 15

in standard form...
\[5x - 2y + 4 = 0\]

Answer 16

Okay first, do you know how to find the slope of that line? you can easily find it from the graph... remember rise over run?

Answer 17

our A = 5, B = -2 and C = 4

Answer 18

@Orion1213 slow down and stop confusing her with unnecessary stuff :P

Answer 19

For perpendicular line, we interchange A and B (property of perpendicular line)...
A = -2, B = 5, therefore in standard form...
\[-2x + 5y + D = 0\]

Answer 20

what is D?

Answer 21

@almartinez26 kindly react if u have a question.... :)

Answer 22

@almartinez26

Answer 23

sorry i lost my connection for a while...

Answer 24

D is the constant of the perpendicular line... we can solve by considering the given point (-5,-1) wherein the perpendicular line passed thru...

Answer 25

It's all good. Thanks for your help but agent0smith explained it to me, i got it now.

Answer 26

ok... no need to continue i think... :)