Question

determine whether the give point is on the circle:: P(-2,3) on 2x^2+2y^2=26

Answer 1

Can you tell me, what will be the radius of the circle?

Answer 2

2sqrt2?

Answer 3

can you tell me how did you do that?

Answer 4

i used the distance formula

Answer 5

do you know, what should be the condition for a point to be inside a circle?

Answer 6

* do you know, what should be the condition for a point to be on a circle?

Answer 7

See first of all

we are given with the equation of a circle as : 2x^2 + 2y^2 = 26

or : 2(x^2 + y^2) = 26

x^2 + y^2 = 13

or x^2 + y^2 = \(\sqrt{13}^2\)

Hence, 13 is considered as the radius of the circle with origin as the centre.

Answer 8

ohhhhhhhhh okok

Answer 9

should i still place the sqrt in 13? or no......

Answer 10

Though, you don't need to do that for solving this question.

We have : \(x^2 + y^2 = 13\\
(-2)^2 + (3)^2 = 13\\
4 + 9 = 13\\
13=13 \)

Which is true^ , thus the point lies ON the circle.

Answer 11

The condition is : x^2 + y^2 = (radius)^2 Taking centre as origin

then for (x,y) point to lie "ON" the circle , x^2 + y^2 must be equal to (radius)^2

Answer 12

kamsahamnida!!!!!!

Answer 13

Sorry, what does that mean? ^

Answer 14

omg sry it means thank u :)

Answer 15

:D You're welcome. Good Luck

Answer 16

감사합니다