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Mathematics 12 Online
OpenStudy (anonymous):

Help please...Determine which, if either, of the following sets form a group with respect to the given operation. I. {1, 2, 3, 4, 5}; multiplication modulo 7 II. the set of integers with respect to multiplication

OpenStudy (kinggeorge):

For the first set, recall that a group must be closed under the given operation. Can you find 2 numbers in the set {1,2,3,4,5} that when multiplied together and reduced modulo 7 are no longer in the set?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

sorry my computer shut down to install updates. I have never done this kind of math before.

OpenStudy (kinggeorge):

Do you know what reduction modulo 7 is?

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

is it prime numbers

OpenStudy (anonymous):

wow I am lost

OpenStudy (kinggeorge):

It means that you divide by 7, and take the remainder. So 10 modulo 7 is 3, 20 modulo 7 is 6, and 28 modulo 7 is 0. Does this make sense?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

i divide 10/7= 1.42

OpenStudy (anonymous):

only II forms a group B) only I forms a group C) neither forms a group D) both form groups

OpenStudy (anonymous):

those are my choices i can pick from

OpenStudy (kinggeorge):

What's the remainder of \(\frac{10}{7}\)? This is just doing the division you learned in elementary school. Don't give me a decimal number.

OpenStudy (anonymous):

3

OpenStudy (kinggeorge):

Right. That's why 10 modulo 7 is 3. Doing a similar thing, 20 modulo 7 is 6. Still with me?

OpenStudy (anonymous):

1. 3/7

OpenStudy (anonymous):

yeah

OpenStudy (kinggeorge):

Notice that 6 is not in your set {1,2,3,4,5}. Can you find two numbers from that set that multiply to 6?

OpenStudy (anonymous):

3,2

OpenStudy (kinggeorge):

Great. But 6 modulo 7, is still 6. Thus, your set is not closed under multiplication modulo 7. Make sense?

OpenStudy (anonymous):

a little

OpenStudy (anonymous):

so neither forms a group

OpenStudy (kinggeorge):

Correct. However, the second one isn't a group for a different reason. Namely, that there are no multiplicative inverses for the integers.

OpenStudy (anonymous):

thank you. I have a few more to do but going to step out for dinner will you be on around 7 tonight?

OpenStudy (kinggeorge):

What time zone?

OpenStudy (anonymous):

eastern

OpenStudy (kinggeorge):

I'm not usually on then, but I'll try to log on for at least a little bit.

OpenStudy (anonymous):

ok thank you

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