Help please...Determine which, if either, of the following sets form a group with respect to the given operation. I. {1, 2, 3, 4, 5}; multiplication modulo 7 II. the set of integers with respect to multiplication
For the first set, recall that a group must be closed under the given operation. Can you find 2 numbers in the set {1,2,3,4,5} that when multiplied together and reduced modulo 7 are no longer in the set?
no
sorry my computer shut down to install updates. I have never done this kind of math before.
Do you know what reduction modulo 7 is?
nope
is it prime numbers
wow I am lost
It means that you divide by 7, and take the remainder. So 10 modulo 7 is 3, 20 modulo 7 is 6, and 28 modulo 7 is 0. Does this make sense?
no
i divide 10/7= 1.42
only II forms a group B) only I forms a group C) neither forms a group D) both form groups
those are my choices i can pick from
What's the remainder of \(\frac{10}{7}\)? This is just doing the division you learned in elementary school. Don't give me a decimal number.
3
Right. That's why 10 modulo 7 is 3. Doing a similar thing, 20 modulo 7 is 6. Still with me?
1. 3/7
yeah
Notice that 6 is not in your set {1,2,3,4,5}. Can you find two numbers from that set that multiply to 6?
3,2
Great. But 6 modulo 7, is still 6. Thus, your set is not closed under multiplication modulo 7. Make sense?
a little
so neither forms a group
Correct. However, the second one isn't a group for a different reason. Namely, that there are no multiplicative inverses for the integers.
thank you. I have a few more to do but going to step out for dinner will you be on around 7 tonight?
What time zone?
eastern
I'm not usually on then, but I'll try to log on for at least a little bit.
ok thank you
Join our real-time social learning platform and learn together with your friends!