An archer releases an arrow from a shoulder height of 1.39 m. When
the arrow hits the target 18 m away, it hits point A. When the target is
removed, the arrow lands 45 m away. Find the maximum height of the
arrow along its parabolic path.
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OpenStudy (anonymous):
bullseye is 8cm wide, other points are 4cm wide
OpenStudy (anonymous):
@AravindG @hba @hartnn help
OpenStudy (hba):
OpenStudy (anonymous):
lol can u help explain??
OpenStudy (hba):
The pdf attached above is the solution.
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OpenStudy (hba):
Do you want me to go step by step?
OpenStudy (anonymous):
yeah
OpenStudy (anonymous):
i want to know how to do it lol
OpenStudy (hba):
the parabola is defined by the equation:
y = f(x) = ax² + bx + c
...where a, b, and c are constant coefficients to be determined. You are given three points:
f(0) = 1.39
f(18) = h ... (height of point A) ... I suspect there's a figure you're not showing us
f(45) = 0
OpenStudy (hba):
You need that height h to solve the problem.
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OpenStudy (anonymous):
OpenStudy (hba):
It will give you 3 equations and 3 unknowns.
OpenStudy (anonymous):
its Activity 2
OpenStudy (anonymous):
@hba ???
OpenStudy (anonymous):
@MathLegend help
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