An archer releases an arrow from a shoulder height of 1.39 m. When the arrow hits the target 18 m away, it hits point A. When the target is removed, the arrow lands 45 m away. Find the maximum height of the arrow along its parabolic path.
bullseye is 8cm wide, other points are 4cm wide
@AravindG @hba @hartnn help
lol can u help explain??
The pdf attached above is the solution.
Do you want me to go step by step?
yeah
i want to know how to do it lol
the parabola is defined by the equation: y = f(x) = ax² + bx + c ...where a, b, and c are constant coefficients to be determined. You are given three points: f(0) = 1.39 f(18) = h ... (height of point A) ... I suspect there's a figure you're not showing us f(45) = 0
You need that height h to solve the problem.
It will give you 3 equations and 3 unknowns.
its Activity 2
@hba ???
@MathLegend help
@ehuman
which one are you doing, height of arrow?
Yeah
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