determine the constant of variation of each equation (-x^2/y)=3 and y=2x
To get the constant of variation for the first equation, write it in the form \(\dfrac{y}{x^2} = k\) To get the constant of variation for the second equation, write it in the form \(\dfrac{y}{x} = k\)
@Hero so is the first on y=-3x^2?! lol i dont really get it
For the first one, divide both sides by -1 to get \(\dfrac{x^2}{y} = -3\) Then multiply both sides by \(y\) Then divide both sides by \(x^2\) Then divide both sides by \(-3\) When you do that, you end up with \(-\dfrac{1}{3} = \dfrac{y}{x^2}\)
But that is the same as \(\dfrac{y}{x^2} = -\dfrac{1}{3}\) Which means \(k = -\dfrac{1}{3}\)
ohhh ok.. thanks you! what bout the second one?! do i do it exactly the same way too?
You simply re-write it in the form given above in my first post.
but theres only one number
For the second one, divide both sides by \(x\) Simple as that
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