Question

Write the equation of the line perpendicular to the line x - 5y = -10 and passing through the point (2,5).
-5y-x-10 all divide by-5

y=-5+2

am I doing this right? @ agent0smith

Answer 1

well yes, but you divided wrong. What's -x divided by 5?

Answer 2

pos 5

Answer 3

No.. Let's try something simpler.. what is 2 divided by 5?

Answer 4

0.4

Answer 5

Write it in fractional form, and don't use a calculator.

Answer 6

2/5

Answer 7

That's what I was looking for.. How about one divided by nine?

Answer 8

1/9

Answer 9

Okay, we're getting there.. How about ☺ divided by ☻ ?

Answer 10

=)

Answer 11

No im kinda serious here

Answer 12

So what is ☺ divided by ☻ ? (You can copy paste the smileys if you can't type them out)

Answer 13

☺/☻

Answer 14

Yes. Now take a guess... what's -x divided by 5?

Answer 15

-x/5

Answer 16

Yup. So you had x - 5y = -10. Divide everything by 5. What do you get (you can divide each term individually)?

Answer 17

-x/5_2

Answer 18

+2

Answer 19

Equals?

Answer 20

y

Answer 21

Okay, actually we were off even earlier - I didn't notice that the negative was wrong. So we had:
x - 5y = -10
Which turned into (after adding 5y to both sides):
x - 5y + 5y = -10 + 5y
x = -10 + 5y
Which then became (after adding 10 to both sides):
x + 10 = -10 +5y + 10
x+10 = 5y
And now if you divide everything by 5, you get:
x/5 + 2 = y, which is the same as:
y = (1/5)x + 2

Answer 22

So what's the slope of that equation?

Answer 23

1/5

Answer 24

1/5x

Answer 25

It actually is 1/5
A slope of the equation in the form y = Mx+b is equal to M

Answer 26

So we know that M = 1/5

Answer 27

You need to write the equation of the line perpendicular to the line that has slope of 1/5. What do we know about slopes of perpendicular lines?

Answer 28

y-5=1/5(x-2) ?

Answer 29

close.. that would be correct if you wanted a parallel equation.

Answer 30

i mean an equation for the line parallel to that one. you want it to be perpendicular.

Answer 31

right, so I am kind of confused on what to do.