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Calculus1 19 Online
OpenStudy (anonymous):

can someone help me find: y' for y=ln(2x^3-3x) ?

OpenStudy (anonymous):

The derivative of ln(u) = 1/u (du)

OpenStudy (anonymous):

So the derivative will be: 1/(2x^3 - 3x) multiplied by (6x^2 - 3) Or, (6x^2 - 3)/(2x^3 - 3x) which can be simplified.

OpenStudy (usukidoll):

this is more of a calculus ii derivative...logarithims

OpenStudy (usukidoll):

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