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Mathematics 15 Online
OpenStudy (anonymous):

HELP!!! EARN A MEDAL!!

OpenStudy (anonymous):

Whats the question? ^_^

OpenStudy (rina.r):

Yeah where is the question? Lol:)

OpenStudy (anonymous):

Triangle XYZ is shown on the coordinate plane below. Triangle XYZ on the coordinate plane with ordered pairs at X 3, negative1, at Y 4, negative 4, at Z 1, negative 2 If triangle XYZ is reflected across the line y = 1 to create triangle X'Y'Z', what is the ordered pair of X'? (3, 3) (3, 1) (-1, -1) (-3, -1)

OpenStudy (anonymous):

x coordinate remains same ... only y coordinate changes. let \[y ^{1}\] be the old coordinate and \[y ^{2}\] the new coordinate then \[y ^{2}=y ^{1}+2\]

OpenStudy (anonymous):

What's the distance from the point X to the line y = 1 ?

OpenStudy (anonymous):

in other words, how many units do you have to go up to go from X to the line y = 1 ?

OpenStudy (anonymous):

the distance of point x from y=1 is 2 units up @shinebrightlikeadimon

OpenStudy (anonymous):

so go another 2 units up from y = 1 (keep the x coordinate the same)

OpenStudy (anonymous):

what do you get?

OpenStudy (anonymous):

3

OpenStudy (anonymous):

Yes. go on

OpenStudy (anonymous):

I need it like this (x,y)

OpenStudy (anonymous):

(1, 3)?

OpenStudy (anonymous):

almost. the Y is correct

OpenStudy (anonymous):

follow the steps again you should get 3,3

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

if you have any questions just ask me :)

OpenStudy (anonymous):

give me a second to do it again

OpenStudy (anonymous):

can you explain that but in like a different way please

OpenStudy (anonymous):

oh nvm

OpenStudy (anonymous):

Did you get it?

OpenStudy (anonymous):

yes thnx you are a big help can you help me on more please?

OpenStudy (anonymous):

Sure just tag me to the other question

OpenStudy (anonymous):

can i send it through message?

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