An electron undergoes a transition from an initial (ni) to a final (nf ) energy state. The energies of the ni and nf energy states are −2.179×10−18J and −8.720×10−20 J, respectively.

Calculate the wavelength (λ) of the light in nanometers (nm) corresponding to the energy change (ΔE) value of this transition. You can use the following values for your calculations:

Planck′s constant (h) = 6.626×10−34 J⋅s
speed of light (c) = 2.998×108 m/s
1 m = 109 nm

Question

An electron undergoes a transition from an initial (ni) to a final (nf ) energy state. The energies of the ni and nf  energy states are −2.179×10−18J and −8.720×10−20 J, respectively.

Calculate the wavelength (λ) of the light in nanometers (nm) corresponding to the energy change (ΔE) value of this transition. You can use the following values for your calculations:

Planck′s constant (h) = 6.626×10−34 J⋅s
speed of light (c) = 2.998×108 m/s
1 m = 109 nm

anonymous · Answer

i think first you take the final energy - the initial energy.Next you use formular E= hv , E : engergy, h is constant, v is frecency

anonymous · Answer

when you have frecency you use this formula to solve wavelenght