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Mathematics 12 Online
OpenStudy (ineedhelp10):

Help in geometry!

OpenStudy (ineedhelp10):

A rectangle is inscribed within a circle. The coordinates are (-2,3); (16,3); (-2,5); and (16,-5). What is the area and circumference of the circle?

OpenStudy (ineedhelp10):

@e.mccormick

OpenStudy (tkhunny):

Have you considered the relationship of the diameter of the circle to the diagonal of the rectangle?

OpenStudy (ineedhelp10):

okay i figured out thee answer, but how can i check my work? @tkhunny

OpenStudy (tkhunny):

Not if you don't post it.

OpenStudy (ineedhelp10):

for Circumference I got 19.7pi and for area i got pi(9.85)^2

OpenStudy (tkhunny):

How did you get those?

OpenStudy (ineedhelp10):

by subtracting -2 from 16 and -5 from 3 which will give me 18 and 8 in absolute value. Then I used the pythagoean theorom. After that I squared root my answer to give me the diameter

OpenStudy (tkhunny):

That's not bad, but we have a little data problem. (-2,3); (16,3); (-2,5); and (16,-5). Are you SURE it's (-2,5) and not (-2,-5) Are you SURE it's (16,-5) and not (16,5) Make sure your figure is a rectangle and not just some old trapezoid.

OpenStudy (ineedhelp10):

oopps my bad, its (-2,-5)

OpenStudy (ineedhelp10):

it is (16,-5) though

OpenStudy (tkhunny):

Fair enough. I might want you to notice that \(\sqrt{388} = 2\sqrt{97}\). This makes the circumference \(2\pi\sqrt{97}\), still not very pretty, and the Area \(\pi(\sqrt{97})^2 = 97\pi\).

OpenStudy (ineedhelp10):

how did you get 97?

OpenStudy (ineedhelp10):

so then this means my answer was wrong?

OpenStudy (tkhunny):

No, if you like the decimals, yours is fine. If you are alert and happen to notice that \(\sqrt{388} = 2\sqrt{97}\), then you can write exact answers. \(\sqrt{97}^{2} = 97\)

OpenStudy (ineedhelp10):

oh okay. thanks

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