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Show that y = x^2 - 3x + 7 is concave up for all values of x.
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It is concave up if its second derivative is always positive, i.e. y ' ' > 0 y' = 2x - 3 y ' ' = 2 So y ' ' is positive always, hence, always concave up.
|dw:1383458667161:dw| What would I need to do after that to show that it is always positive? A table of values?
y ' ' = 2 means that the second derivative is a positive number called 2. That alone is sufficient!
I see. Thank you!
welcome.
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