Why the entropy become higher at higher temperature,if s=Q/T?
\[ \Delta S = \frac{Q}{T}\] is used for quasistatic mostly isothermal processes (when the object that you're adding energy to is large enough that the heat you're putting in doesn't greatly change its temperature).
Are you asking why entropy becomes higher as temperature becomes higher, even though it is supposed to be a inverse proportional relationship?
In something like adding enough energy to a glass of water to make it heat up (maintaining constant volume) you can make the equation \[\mathrm {d}S = \frac{C}{T}\mathrm {d}T \] Where C is the energy capacity of liquid water \[\Delta S = S_f - S_i = C\int_{T_i}^{T_f}\frac{1}{T}\mathrm {d}T =C \ ln \Biggr(\frac{T_f}{T_i} \Biggr) \] And see that the change in entropy is positive with an increase in temperature.
Join our real-time social learning platform and learn together with your friends!