Question

dx/dt=k(a-x)

Answer 1

dx/dt=k(a-x)^2\[dx/dt = k(a-x)^2\]

Answer 2

dx/(a-x)=k dt
now integral
integral(dx/(a-x))=integral (k dt)
so
-ln|a-x|=k(t-t0)
ln|a-x|=k(t0-t)
so
a-x=exp(k(t0-t))

Answer 3

\[dx/dt = k(a-x)^2\]

Answer 4

do just like that

Answer 5

but it has different integral in left side

Answer 6

dx/(a-x)^2=k dt
now integral
integral(dx/(a-x)^2)=integral (k dt)
so
1/(a-x)=k(t-t0)

can you go on?

Answer 7

Thank's Mr amoodarya....

Answer 8

your welcome !
was it useful ?

Answer 9

\[\int\limits dx/(a-x)^2 = \int\limits k.dt\]