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Mathematics 10 Online
OpenStudy (anonymous):

find the derivative of y

OpenStudy (gorv):

dy/dx

OpenStudy (anonymous):

\[y = t^(3 - e) \]

OpenStudy (gorv):

that is t^(3-e)???

OpenStudy (anonymous):

yes isnt the derivative a^x *lna ?

OpenStudy (anonymous):

or would i use chain ?

OpenStudy (gorv):

it is a simple derivative

OpenStudy (gorv):

3-e is a contant like t^2

OpenStudy (gorv):

can u solve now???

OpenStudy (gorv):

@Qawi

OpenStudy (anonymous):

let me try urmm F'(x) = t ln t g(x) = (e - 3) g'(x) = e

OpenStudy (gorv):

no e is constant g'(x)=0

OpenStudy (anonymous):

i thought the derivative of e was e

OpenStudy (gorv):

that is e^x

OpenStudy (gorv):

d(e^x)/dx= e^x

OpenStudy (anonymous):

oh so if it's just e the derivative is 0 ?

OpenStudy (anonymous):

sooo would it be t(3-e)ln(t) * 0

OpenStudy (gorv):

y=t^(3-e) dy/dx=(3-e)*t^((3-e)-1) =(3-e)*t^(2-e)

OpenStudy (gorv):

@Qawi

OpenStudy (anonymous):

hmm

OpenStudy (gorv):

gotcha???

OpenStudy (anonymous):

tx = tx ln(t)?

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