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find the derivative of y
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dy/dx
\[y = t^(3 - e) \]
that is t^(3-e)???
yes isnt the derivative a^x *lna ?
or would i use chain ?
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it is a simple derivative
3-e is a contant like t^2
can u solve now???
@Qawi
let me try urmm F'(x) = t ln t g(x) = (e - 3) g'(x) = e
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no e is constant g'(x)=0
i thought the derivative of e was e
that is e^x
d(e^x)/dx= e^x
oh so if it's just e the derivative is 0 ?
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sooo would it be t(3-e)ln(t) * 0
y=t^(3-e) dy/dx=(3-e)*t^((3-e)-1) =(3-e)*t^(2-e)
@Qawi
hmm
gotcha???
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tx = tx ln(t)?
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