What are the explicit equation and domain for a geometric sequence with a first term of 2 and a second term of -8?
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The calculator ndoesnt like ur problem...
lmfao calculator nvr helps anymoar
>.<
The explicit equation is \[a _{n}=a _{1}* q ^{n-1}\]In your case \[a _{n}= 2 * (-4)^{n-1}\] or to put it more nicely: \[a _{n}= 2 * \frac{ (-4)^{n} }{ 4 } = \frac{ (-4)^{n} }{ 2 }\] (q is -4 because you divide the second term by the first) I'm not sure about the domain though. I tried finding the minimum/maximum but the expression I got was \[\frac{ (-4)^{n} }{ 2 } + \frac{ (-4) ^{n}}{ 8 }\] which is positive for all even n-s and negative for odd ones.
a. an = 2(-8)n - 1; all integers where n ≥ 1 b. an = 2(-8)n - 1; all integers where n ≥ 0 c. an = 2(-4)n - 1; all integers where n ≥ 0 d. an = 2(-4)n - 1; all integers where n ≥ 1 uhhh these r the options >_< im thinking mayb a?
It's d because it would be a rational number if you plugged in 0 for n, so it has to be greater than or equal to 1.
okay :D thank you
glad to help :)
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