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What is the solution of log3x - 12 729 = 6? the 3x-12 is like lower than log
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\(\huge log_{3x - 12}(729) = 6\quad ?\)
yes like that
\[\Large \log_{3x - 12} 729 = 6\]\[\Large \log_{B} A = C\]means\[\Large A = B^{C}\]
hmm you know the change of base rule, right?
\[\Large \log_{3x - 12}(729) = 6\quad means \quad (3x - 12)^{6} = 729\]
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729 = 3^6 Solve for x.
uhm so like distribute th e6 to the 3x and the 12?
\[\Large (3x - 12)^{6} = 729 = 3^{6}\]. Both are raised to 6. Therefore, 3x - 12 = 3. Solve for x.
so it would be 5?
Yes, x = 5. Another way to look at it is: (3x - 12)^6 = 729 Find the sixth root on both sides (that is, raise both sides to the power 1/6): 3x - 12 = 729^(1/6) = 3
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