Question

The position s of a point (in feet) is given as a function of time t (in seconds).
s = 2/t − 2/t^2; t = 2
(a) Find its acceleration as a function of t.
s''(t) =
(b) Find the point's acceleration at the specified time.
s''(2) =

Answer 1

$$a(x) = \frac{d^2 s}{dt^2}$$

Answer 2

Its s= \[\frac{ 2 }{ t }-\frac{ 2 }{ t^2 }\] t=2

Answer 3

s''= \[(4/t^{3})-(12/t ^{4})\]
s''(2)= -0.25 m/s^2

Answer 4

@archanatikayatray its actually 4/t^3-12/t^4
Thank you!

Answer 5

@arshia93 You're Welcome