Question

Five weeks after the introduction of a new toy, the manufacturer found that the demand for the toy was modeled by f(x)=x^2+5x+4/x^2+6x-7 - 1/2 , while the company’s supply capability was modeled by g(x)= -0.89x^2+850x-50/800x+70.5 . Here x is the number of weeks the toy has been on the market, and the values of f(x) and g(x) are in millions of toy units. About how many weeks after the toy was introduced did supply equal demand? Round to the nearest whole number of weeks.

Answer 1

hi @madiluv9429 I'm reading your question and will try to help out with it

Answer 2

okay thank you

Answer 3

let me do some work real fast… and from there see if i can explain it

Answer 4

okay

Answer 5

\[f(x)=\frac{ x^{2}+5x+4 }{ x^{2}+6x-7 }-\frac{ 1 }{ 2 }\]

is that what your f(x) should look like

Answer 6

the one half is actually 1/x

sorry

Answer 7

tough question, but when i graphed both equations i see the number of weeks would equal 3.37

Answer 8

or the nearest whole =3weeks

Answer 9

i'm not sure how to explain, but i can post a pic of my graphing

Answer 10

its very confusing because i got the same answer but my answers are

A. 74 weeks

B. 80 weeks

C. 76 weeks

Answer 11

ok i see now

Answer 12

i zoomed way out on my graph and saw another intersection

Answer 13

@ 75.7 weeks or 76

Answer 14

ohkay can you help me on the other questions i got wrong

Answer 15

iam willing to give it a shot

Answer 16

okay give me two secs

Answer 17

np

Answer 18

his graph of a function is a translation of y=2/x . What is an equation for the function?

Answer 19

https://study.ashworthcollege.edu/access/content/group/59841a3a-ae83-40e0-9ad2-cdbb53b336a0/Algebra%20II%20Part%202/algebra2_exam_8_files/mc005-2.jpg

Answer 20

sec

Answer 21

the answers are
A.y=2/x-3 -5
B. y=2/x-5 -3
C. y=2/x-5 +3

Answer 22

y=(2/x-5))-3

or b

Answer 23

do you know how to do transformations

Answer 24

I'm sure you do

Answer 25

yes i do but this is suppose to be algebra 2 and non of this is in my books so i am pretty confused and this is my last class til i graduate so i need to pass

Answer 26

Simplify the difference.
\[n ^{2}-10n+24/n ^{2}-13n+42 - 9/n-7\]

Answer 27

\[\frac{ n^{2}-10n+24 }{ n^{2}-13n+42 }-\frac{ 9 }{ n-7 }\]

is this how it looks

Answer 28

yes

Answer 29

k now i will factor the numerator and denominator of the left side for….sec

Answer 30

\[\frac{ (n-4)(n-6) }{ (n-6)(n-7) }-\frac{ 9 }{ (n-7) }\]

Answer 31

ok so you took away the exponents

Answer 32

yes now we cancel like terms of the num and denim

Answer 33

denom*

Answer 34

so we cancel out n-4 and n-6 and n-6 and n-7

Answer 35

just looking at the left side, we will cancel the (n-6) from top and bottom

Answer 36

ok because theres n-6 onn top and bottom?

Answer 37

yesm and that will leave us with
\[\frac{ (n-4) }{ (n-7) }-\frac{ 9 }{ (n-7) }\]

Answer 38

ok now we cancel out the n-7 aswell?

Answer 39

nope that will remain, that is our common denominator

Answer 40

\[\frac{ (n-4)-9 }{ (n-7) }\]

Answer 41

so we just combined the n-7 and kept the 9 as a negative

Answer 42

yes

Answer 43

you can still write it as before
\[\frac{ (n-4) }{ (n-7) }-\frac{ 9 }{ (n-7) }\]

Answer 44

because both (n-4) and 9 are being divided by the same denominator (n-7)

Answer 45

they just wanted it simplified! thats all

Answer 46

a. https://study.ashworthcollege.edu/access/content/group/3deb3864-16e6-41b5-8cfd-6102f85fcfab/algebra2_exam_8_files/mc017-2.jpg
c. https://study.ashworthcollege.edu/access/content/group/3deb3864-16e6-41b5-8cfd-6102f85fcfab/algebra2_exam_8_files/mc017-4.jpg
d. https://study.ashworthcollege.edu/access/content/group/3deb3864-16e6-41b5-8cfd-6102f85fcfab/algebra2_exam_8_files/mc017-5.jpg

Answer 47

im not able to see them

Answer 48

oh wait weird

Answer 49

those are the given answers?

Answer 50

yes

Answer 51

i want to say a because it has the same denominator i dunno where the 13 came from one sec

Answer 52

was there a b answer

Answer 53

you posted the three answers above a, c, and d

Answer 54

i put be and i got it wrong

Answer 55

what was answer b?

Answer 56

you didn't post it earlier

Answer 57

n-4/n-7

Answer 58

what about the 9? (n-4)-9/(n-7)

Answer 59

there was no 9

Answer 60

did they give you the right answer?

Answer 61

no i have to figure out on my own

Answer 62

they allow multiple chances to answer?

Answer 63

i say its a because it shows the same denominator, but idk where the 13 came from

Answer 64

yes i do online and so everything except the final is multiple choice answers

Answer 65

9+4 is 13 but i don't see how that would be legit

Answer 66

i dont know thats why im so confused

Answer 67

or -4- -9= -13

Answer 68

oh i know whats up

Answer 69

should have just factored the left side denim first to find the common denim

Answer 70

@Mertsj might be able to help

Answer 71

okay

Answer 72

Simplify the difference.
n^2−10n+24/n^2−13n+42−9/n−7

is the initial question @merts

Answer 73

The problem you have to solve is f(x)=g(x)

Answer 74

@Mertsj she has a new question

Answer 75

simplifying
\[\frac{ n^{2}-10n+24 }{ n^{2}-13n+42 }-\frac{ 9 }{ n-7 }\]

Answer 76

then factored, had a common denominator, n got stuck

Answer 77

\[\frac{n-4}{n-7}-\frac{9}{n-7}=\frac{n-4-9}{n-7}=\frac{n-13}{n-7}\]

Answer 78

i was right but i didn't know where the -13 came from

Answer 79

yep

Answer 80

@madiluv9429 it was A :)

Answer 81

okay thank you i need help on other questions as well

Answer 82

ok

Answer 83

Simplify the sum
4/m+9 + 5/m^2-81

Answer 84

\[\frac{ 4 }{ m+9 }+\frac{ 5 }{ m ^{2}-81 }\]
like this?

Answer 85

@madiluv9429

Answer 86

yes

Answer 87

ok
\[\frac{ 4 }{ m+9 }+\frac{ 5 }{ (m+9)(m-9) }\]

Answer 88

you find a common number that will go into 81 and 9 and that is 9 is that right

Answer 89

yep when m^2-81 factored is (m+9)(m-9)

Answer 90

ohhh ohkay than what

Answer 91

i think it is just 9/m+9